New answers tagged passwords
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The proposed method requires 24 additional random BIP-39 words. The additional words together with the real 24-word passphrase are permutated in a word manner. The result has $2\cdot 10^{37}$ combinations that have $\approx 2^{124}$ bits of security. 8-word passphrase are already had more security than this $\approx 2^{139}$[1]
If a random permutation is ...
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